Split the string when alphabet is found next to a number using regex Python -


i have string this

string = "3,197working age population"

i want break string such when number 3,197 ends , working age population starts using regex or other efficient method. in short need 3,197

you may have @ itertools.takewhile:

from itertools import takewhile  string = "3,197working age population" r = ''.join(takewhile(lambda x: not x.isalpha(), string)) print(r) # '3,197'

takes items string while alphabet has not been reached. result reformed string using join


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