linux - how to work with 'while ..; do..; done' in bash -


this question has answer here:

i having trouble using command in bash operation. following have:

cat namelist | while read line; awk '$1 == $line {print $0}' jan.txt; done

the namelist unrepeated namelist each name on each line. , jan.txt file of information these:

ermartin pts/10       tue jan 19 09:49 - 10:15  (00:26)     171.66.208.139 sdou     pts/6        tue jan 19 01:52 - 22:20 (9+20:27)    131.243.186.99 sdou     pts/2        tue jan 19 01:20 - 22:20 (9+20:59)    131.243.186.99 phu      pts/2        sat jan 16 12:21 - 15:13  (02:52)     lbl-ipsec-7667.dhcp.lbl.gov phu      pts/2        sat jan 16 10:07 - 12:01  (01:54)     lbl-ipsec-7622.dhcp.lbl.gov sjames   pts/5        fri jan 15 12:06 - 13:06  (01:00)     lakshmi.lbl.gov ermartin pts/2        fri jan 15 08:36 - 12:43  (04:07)     171.66.208.134 ermartin pts/2        fri jan 15 08:31 - 08:36  (00:05)     171.66.208.134 camitche pts/4        thu jan 14 15:18 - 20:47  (05:28)     171.66.208.134 ermartin pts/2        thu jan 14 13:20 - 15:57  (02:36)     171.66.208.139 ermartin pts/2        thu jan 14 12:35 - 13:00  (00:25)     171.66.208.139 sjames   pts/2        thu jan 14 06:17 - 06:27  (00:09)     phys1.als.lbl.gov sjames   pts/2        thu jan 14 06:17 - 06:17  (00:00)     phys1.als.lbl.gov ermartin pts/0        wed jan 13 15:19 - 15:50  (00:31)     171.66.208.139 ermartin pts/0        wed jan 13 07:55 - 08:09  (00:13)     c-24-130-14-154.hsd1.ca.comcast.net

i trying match names in namelist file , operation each line of information in file when did $1 == $line, says it's error. how make use of command properly?

is possible loop on months , print them title like: 

[jan]  sjames ...hours  sdou ...hours   [feb]  sjames ...hours  sdou ...hours

first, awk , shell not share variables. is, however, possible transfer shell variable awk variable using -v option. following works , change code adding -v line="$line" option:

cat namelist | while read line; awk -v line="$line" '$1 == line {print $0}' jan.txt; done

note awk references line variable line no dollar sign.

a possible replacement above pipeline is:

awk 'fnr==nr{a[$1]; next;} $1 in a' namelist jan.txt

here, associative array a keeps track of names in namelist , uses decide whether print lines in jan.txt.

if not going more processing of data (but gather opposite true), then, shellter suggests in comments, above replaced with:

grep -ff namelist jan.txt

if want calculate time used users in namelist, try:

$ awk -f'[ +:()]+' 'fnr==nr{a[$1]; next;} !($1 in a){next} nf==13{b[$1]+=$12+60*$11} nf==14{b[$1]+=$13+60*($12+24*$11)} end{for (n in b)print n,b[n]}' namelist jan.txt

as example, consider namelist:

$ cat namelist  sdou phu

the calculated times are:

$ awk -f'[ +:()]+' 'fnr==nr{a[$1]; next;} !($1 in a){next} nf==13{b[$1]+=$12+60*$11} nf==14{b[$1]+=$13+60*($12+24*$11)} end{for (n in b)print n,b[n]}' namelist jan.txt phu 286 sdou 28406

for readability, may easier see same code spread on multiple lines:

awk -f'[ +:()]+' '   fnr==nr{     a[$1]     next   }    !($1 in a){     next   }    nf==13{     b[$1]+=$12+60*$11   }    nf==14{     b[$1]+=$13+60*($12+24*$11)   }    end{     (n in b)       print n,b[n]   }   ' namelist jan.txt phu 286

to track usage user , month:

$ awk -f'[ +:()]+' 'fnr==nr{a[$1]; next;} !($1 in a){next} nf==13{b[$1"["$4"]"]+=$12+60*$11} nf==14{b[$1"["$4"]"]+=$13+60*($12+24*$11)} end{for (n in b)print n,b[n]}' namelist jan.txt phu[jan] 286 sdou[jan] 28406

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