bash - for loop output formatting: add newline with a description and space -

i'm running through list of files cat , redirecting of output single file using loop. loop works i'm looking way add descriptor line before each file's contents dumped , add space before each new file entry. here script.

#!/bin/bash  files=$(ls -l /home/user/*.txt | awk 'nr>=2 {print $9}')  in $files; /bin/cat "$i" >> "/home/user/catfiles.txt" done 

my output looks this:

 spawn ssh user@x.x.x.x  run $command  quit  spawn ssh user@x.x.x.x  run $command  quit 

i this:

 "description first file here"  spawn ssh user@x.x.x.x  run $command  quit  <space>  "description second file here"  spawn ssh user@x.x.x.x  run $command  quit  <space> 

update: file description name need vary file using actual file name.

"this $file1" "this $file2"  etc,etc.. 

this merge them require it:

for f in /home/user/*.txt;do     echo "this ${f##*/}" >> /home/user/catfiles.txt     /bin/cat "${f}" >> /home/user/catfiles.txt     echo >> /home/user/catfiles.txt done 

the file name printed without path. if want path printed, too, replace ${f##*/} ${f}.

update

${variable##pattern} called parameter substitution. bash search pattern in variable , remove longest match. in case variable f , pattern */ matches string ends slash. double hash ## indicates remove longest string in f can matched */. since f path match , remove , including last /, leaving filename. bash documentation has further , more detailed info on subject. alternatively, can search in man bash parameter expansion.