sql - How would I iterate through a list in SAS and translate / replace each piece with an imported mapping? -


i new sas , i'm not sure how go replacing each part of dataset have_1 translation data set (have_2) imported sas. 

 data have_1     1111 1234 2222     2938 3849     1234 9388     ...     2222 2222     data have_2     1111     1234 b     2222 c     2938 d     3849 e     ...     9388 f   data want     b c     d e     b f     c c

whether or not want replace them, proc format in sas - maps value value.

here how might that. note cannot reuse original 3 variables (since they're numeric), rename , drop combination if wanted same variable names.

using format statement directly achieve same result visually (but underlying value still numeric one).

data have_1;   infile datalines missover;   input var1-var3; datalines; 1111 1234 2222 2938 3849 1234 9388 2222 2222 ;;;; run;    data have_2;   input numval charval $; datalines; 1111 1234 b 2222 c 2938 d 3849 e 9388 f ;;;; run;  data for_fmt;   set have_2;   start=numval;   label=charval; *could use rename these makes last bit more confusing read;   retain fmtname 'charvalf' type 'n';   output;    if _n_=1 do;  *now define 'other' value (hlo='o') non-matched records;     hlo='o';     label=' ';     call missing(start); *unnecessary avoids duplicate start values , less confusing output;     output;   end; run;  proc format cntlin=for_fmt; quit;  data want;   set have_1;   format var1-var3 charvalf1.;   *option 1 - visual format only;   array var[3];   array varc[3] $;               *option 2 - new set of vars w/char vals;   _i = 1 dim(var);     varc[_i] = put(var[_i],charvalf1.);   end; run;

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