c# - Setting the file name returned by ASP .NET Web API -

i looking set name of file being returned asp .net web api. returns in name of parameters being passed in url. if need returned abc.json

public class newtestcontroller : apicontroller { public string getdetails([fromuri] string[] id) {using (oracleconnection dbconn = new oracleconnection("data source=j;password=c;persist security info=true;user id=t"))     {         var inconditions = id.distinct().toarray();         var srtcon = string.join(",", inconditions);         dataset userdataset = new dataset();         var strquery = @"select                         * stpr_study stpr_study.std_ref in (" + srtcon + ")";         oraclecommand selectcommand = new oraclecommand(strquery, dbconn);         oracledataadapter adapter = new oracledataadapter(selectcommand);         datatable selectresults = new datatable();         adapter.fill(selectresults);         return jsonconvert.serializeobject(selectresults); }}} 

i did see in other forums using content-disposition not using httpresponse in code. how can done. thanks

i tried below

 oraclecommand selectcommand = new oraclecommand(strquery, dbconn);             oracledataadapter adapter = new     oracledataadapter(selectcommand);             datatable selectresults = new datatable();             adapter.fill(selectresults);             string result =  jsonconvert.serializeobject(selectresults);             httpresponsemessage response = new httpresponsemessage();             response.statuscode = httpstatuscode.ok;             response.content = new streamcontent(result);             response.content.headers.contentdisposition = new contentdispositionheadervalue("attachment")             {                 filename = "abc.json"             };      return(result); 

but throws error in streamcontent saying,the best overloaded method match has invalid arguments in streamconent

you can use createresponse method of request object below

    public httpresponsemessage get()     {         string filename = "abc.json";         return request.createresponse(httpstatuscode.ok, filename);     } 

edit 1:

   string contentdisposition = "inline; filename=abc.json";    httpresponsemessage response = request.createresponse(httpstatuscode.ok, byteinfo, mediatypeheadervalue.parse("application/json"));    response.content.headers.contentdisposition = contentdispositionheadervalue.parse(contentdisposition);    return response;